199A - Hexadecimal's theorem - CodeForces Solution


brute force constructive algorithms implementation number theory *900

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Python Code:

def fib_num(number, fib_list):
    while fib_list[-1] != number:
        fib_list.append(fib_list[-1] + fib_list[-2])
    return fib_list

number = int(input())
fib_list = [0, 1]
if number == 0:
    print('0 0 0')
elif number == 1:
    print('0 0 1')
else:
    fib_num(number, fib_list)
    print(0, fib_list[-2], fib_list[-3])


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